4z+5(7z-3)=9(z-5)

Solution for 4z+5(7z-3)=9(z-5) equation:

4z+5(7z-3)=9(z-5)

We move all terms to the left:

4z+5(7z-3)-(9(z-5))=0

We multiply parentheses

4z+35z-(9(z-5))-15=0


We calculate terms in parentheses: -(9(z-5)), so:

9(z-5)

We multiply parentheses

9z-45

Back to the equation:

-(9z-45)


We add all the numbers together, and all the variables

39z-(9z-45)-15=0

We get rid of parentheses

39z-9z+45-15=0

We add all the numbers together, and all the variables

30z+30=0

We move all terms containing z to the left, all other terms to the right

30z=-30

z=-30/30

z=-1