4z+64=4(4z+4)

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Solution for 4z+64=4(4z+4) equation: 



4z+64=4(4z+4)

We move all terms to the left:

4z+64-(4(4z+4))=0



We calculate terms in parentheses: -(4(4z+4)), so:

4(4z+4)

We multiply parentheses

16z+16

Back to the equation:

-(16z+16)



We get rid of parentheses

4z-16z-16+64=0

We add all the numbers together, and all the variables

-12z+48=0

We move all terms containing z to the left, all other terms to the right

-12z=-48

z=-48/-12

z=+4

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