4z+6=3(2z-2)

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Solution for 4z+6=3(2z-2) equation: 



4z+6=3(2z-2)

We move all terms to the left:

4z+6-(3(2z-2))=0



We calculate terms in parentheses: -(3(2z-2)), so:

3(2z-2)

We multiply parentheses

6z-6

Back to the equation:

-(6z-6)



We get rid of parentheses

4z-6z+6+6=0

We add all the numbers together, and all the variables

-2z+12=0

We move all terms containing z to the left, all other terms to the right

-2z=-12

z=-12/-2

z=+6

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