4z+6=4(z+3)-6

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Solution for 4z+6=4(z+3)-6 equation: 



4z+6=4(z+3)-6

We move all terms to the left:

4z+6-(4(z+3)-6)=0



We calculate terms in parentheses: -(4(z+3)-6), so:

4(z+3)-6

We multiply parentheses

4z+12-6

We add all the numbers together, and all the variables

4z+6

Back to the equation:

-(4z+6)



We get rid of parentheses

4z-4z-6+6=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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