4z+9+3(2z)=129

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Solution for 4z+9+3(2z)=129 equation:


Simplifying
4z + 9 + 3(2z) = 129

Remove parenthesis around (2z)
4z + 9 + 3 * 2z = 129

Multiply 3 * 2
4z + 9 + 6z = 129

Reorder the terms:
9 + 4z + 6z = 129

Combine like terms: 4z + 6z = 10z
9 + 10z = 129

Solving
9 + 10z = 129

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 10z = 129 + -9

Combine like terms: 9 + -9 = 0
0 + 10z = 129 + -9
10z = 129 + -9

Combine like terms: 129 + -9 = 120
10z = 120

Divide each side by '10'.
z = 12

Simplifying
z = 12

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