4z+z+1=7(z-1)

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Solution for 4z+z+1=7(z-1) equation:


Simplifying
4z + z + 1 = 7(z + -1)

Reorder the terms:
1 + 4z + z = 7(z + -1)

Combine like terms: 4z + z = 5z
1 + 5z = 7(z + -1)

Reorder the terms:
1 + 5z = 7(-1 + z)
1 + 5z = (-1 * 7 + z * 7)
1 + 5z = (-7 + 7z)

Solving
1 + 5z = -7 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
1 + 5z + -7z = -7 + 7z + -7z

Combine like terms: 5z + -7z = -2z
1 + -2z = -7 + 7z + -7z

Combine like terms: 7z + -7z = 0
1 + -2z = -7 + 0
1 + -2z = -7

Add '-1' to each side of the equation.
1 + -1 + -2z = -7 + -1

Combine like terms: 1 + -1 = 0
0 + -2z = -7 + -1
-2z = -7 + -1

Combine like terms: -7 + -1 = -8
-2z = -8

Divide each side by '-2'.
z = 4

Simplifying
z = 4

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