4z-(z+6)=32-4

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Solution for 4z-(z+6)=32-4 equation: 



4z-(z+6)=32-4

We move all terms to the left:

4z-(z+6)-(32-4)=0

We add all the numbers together, and all the variables

4z-(z+6)-28=0

We get rid of parentheses

4z-z-6-28=0

We add all the numbers together, and all the variables

3z-34=0

We move all terms containing z to the left, all other terms to the right

3z=34

z=34/3

z=11+1/3

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