4z-12=z+27

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Solution for 4z-12=z+27 equation:



4z-12=z+27
We move all terms to the left:
4z-12-(z+27)=0
We get rid of parentheses
4z-z-27-12=0
We add all the numbers together, and all the variables
3z-39=0
We move all terms containing z to the left, all other terms to the right
3z=39
z=39/3
z=13

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