4z-2(3z+2)+18=-40

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Solution for 4z-2(3z+2)+18=-40 equation: 



4z-2(3z+2)+18=-40

We move all terms to the left:

4z-2(3z+2)+18-(-40)=0

We add all the numbers together, and all the variables

4z-2(3z+2)+58=0

We multiply parentheses

4z-6z-4+58=0

We add all the numbers together, and all the variables

-2z+54=0

We move all terms containing z to the left, all other terms to the right

-2z=-54

z=-54/-2

z=+27

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