4z-2+4z-2+3z+3z=122

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Solution for 4z-2+4z-2+3z+3z=122 equation: 



4z-2+4z-2+3z+3z=122

We move all terms to the left:

4z-2+4z-2+3z+3z-(122)=0

We add all the numbers together, and all the variables

14z-126=0

We move all terms containing z to the left, all other terms to the right

14z=126

z=126/14

z=9

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