4z-2z(1+3)=32

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Solution for 4z-2z(1+3)=32 equation: 



4z-2z(1+3)=32

We move all terms to the left:

4z-2z(1+3)-(32)=0

We add all the numbers together, and all the variables

4z-2z4-32=0

We add all the numbers together, and all the variables

-2z^4+4z-32=0

We do not support ezpression: z^4

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