4z-3(z+1)=3(z-3)-2z

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Solution for 4z-3(z+1)=3(z-3)-2z equation: 



4z-3(z+1)=3(z-3)-2z

We move all terms to the left:

4z-3(z+1)-(3(z-3)-2z)=0

We multiply parentheses

4z-3z-(3(z-3)-2z)-3=0



We calculate terms in parentheses: -(3(z-3)-2z), so:

3(z-3)-2z

We add all the numbers together, and all the variables

-2z+3(z-3)

We multiply parentheses

-2z+3z-9

We add all the numbers together, and all the variables

z-9

Back to the equation:

-(z-9)



We add all the numbers together, and all the variables

z-(z-9)-3=0

We get rid of parentheses

z-z+9-3=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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