4z-3(z+1)=4(z-3)-3z

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Solution for 4z-3(z+1)=4(z-3)-3z equation:


Simplifying
4z + -3(z + 1) = 4(z + -3) + -3z

Reorder the terms:
4z + -3(1 + z) = 4(z + -3) + -3z
4z + (1 * -3 + z * -3) = 4(z + -3) + -3z
4z + (-3 + -3z) = 4(z + -3) + -3z

Reorder the terms:
-3 + 4z + -3z = 4(z + -3) + -3z

Combine like terms: 4z + -3z = 1z
-3 + 1z = 4(z + -3) + -3z

Reorder the terms:
-3 + 1z = 4(-3 + z) + -3z
-3 + 1z = (-3 * 4 + z * 4) + -3z
-3 + 1z = (-12 + 4z) + -3z

Combine like terms: 4z + -3z = 1z
-3 + 1z = -12 + 1z

Add '-1z' to each side of the equation.
-3 + 1z + -1z = -12 + 1z + -1z

Combine like terms: 1z + -1z = 0
-3 + 0 = -12 + 1z + -1z
-3 = -12 + 1z + -1z

Combine like terms: 1z + -1z = 0
-3 = -12 + 0
-3 = -12

Solving
-3 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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