4z-3(z+3)=2(z-3)-z

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Solution for 4z-3(z+3)=2(z-3)-z equation:


Simplifying
4z + -3(z + 3) = 2(z + -3) + -1z

Reorder the terms:
4z + -3(3 + z) = 2(z + -3) + -1z
4z + (3 * -3 + z * -3) = 2(z + -3) + -1z
4z + (-9 + -3z) = 2(z + -3) + -1z

Reorder the terms:
-9 + 4z + -3z = 2(z + -3) + -1z

Combine like terms: 4z + -3z = 1z
-9 + 1z = 2(z + -3) + -1z

Reorder the terms:
-9 + 1z = 2(-3 + z) + -1z
-9 + 1z = (-3 * 2 + z * 2) + -1z
-9 + 1z = (-6 + 2z) + -1z

Combine like terms: 2z + -1z = 1z
-9 + 1z = -6 + 1z

Add '-1z' to each side of the equation.
-9 + 1z + -1z = -6 + 1z + -1z

Combine like terms: 1z + -1z = 0
-9 + 0 = -6 + 1z + -1z
-9 = -6 + 1z + -1z

Combine like terms: 1z + -1z = 0
-9 = -6 + 0
-9 = -6

Solving
-9 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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