4z-35=10z-125

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Solution for 4z-35=10z-125 equation: 



4z-35=10z-125

We move all terms to the left:

4z-35-(10z-125)=0

We get rid of parentheses

4z-10z+125-35=0

We add all the numbers together, and all the variables

-6z+90=0

We move all terms containing z to the left, all other terms to the right

-6z=-90

z=-90/-6

z=+15

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