4z-42+3z-23=z+47

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Solution for 4z-42+3z-23=z+47 equation: 



4z-42+3z-23=z+47

We move all terms to the left:

4z-42+3z-23-(z+47)=0

We add all the numbers together, and all the variables

7z-(z+47)-65=0

We get rid of parentheses

7z-z-47-65=0

We add all the numbers together, and all the variables

6z-112=0

We move all terms containing z to the left, all other terms to the right

6z=112

z=112/6

z=18+2/3

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