4z-5=9+2(z+1)

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Solution for 4z-5=9+2(z+1) equation: 



4z-5=9+2(z+1)

We move all terms to the left:

4z-5-(9+2(z+1))=0



We calculate terms in parentheses: -(9+2(z+1)), so:

9+2(z+1)

determiningTheFunctionDomain
2(z+1)+9

We multiply parentheses

2z+2+9

We add all the numbers together, and all the variables

2z+11

Back to the equation:

-(2z+11)



We get rid of parentheses

4z-2z-11-5=0

We add all the numbers together, and all the variables

2z-16=0

We move all terms containing z to the left, all other terms to the right

2z=16

z=16/2

z=8

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