4z-6=6(z+2)+5

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Solution for 4z-6=6(z+2)+5 equation:



4z-6=6(z+2)+5
We move all terms to the left:
4z-6-(6(z+2)+5)=0
We calculate terms in parentheses: -(6(z+2)+5), so:
6(z+2)+5
We multiply parentheses
6z+12+5
We add all the numbers together, and all the variables
6z+17
Back to the equation:
-(6z+17)
We get rid of parentheses
4z-6z-17-6=0
We add all the numbers together, and all the variables
-2z-23=0
We move all terms containing z to the left, all other terms to the right
-2z=23
z=23/-2
z=-11+1/2

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