4z2=30

Solution for 4z2=30 equation:

4z^2=30

We move all terms to the left:

4z^2-(30)=0

a = 4; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·4·(-30)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*4}=\frac{0-4\sqrt{30}}{8}
=-\frac{4\sqrt{30}}{8}
=-\frac{\sqrt{30}}{2}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*4}=\frac{0+4\sqrt{30}}{8}
=\frac{4\sqrt{30}}{8}
=\frac{\sqrt{30}}{2}
$