4z=z+12

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Solution for 4z=z+12 equation: 



4z=z+12

We move all terms to the left:

4z-(z+12)=0

We get rid of parentheses

4z-z-12=0

We add all the numbers together, and all the variables

3z-12=0

We move all terms containing z to the left, all other terms to the right

3z=12

z=12/3

z=4

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