5((-v/5)+2)=5(3v)

Solution for 5((-v/5)+2)=5(3v) equation:

5((-v/5)+2)=5(3v)

We move all terms to the left:

5((-v/5)+2)-(5(3v))=0

determiningTheFunctionDomain
5((-v/5)+2)-53v=0

We add all the numbers together, and all the variables

-53v+5((-v/5)+2)=0

We multiply all the terms by the denominator


-53v*5)+2)+5((-v=0

We add all the numbers together, and all the variables

-1v-53v*5)+2)+5((=0

Wy multiply elements

-265v^2-1v=0

a = -265; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-265)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-265}=\frac{0}{-530}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-265}=\frac{2}{-530}
=-1/265
$