5((215-20y)/5)+20y=215

Solution for 5((215-20y)/5)+20y=215 equation:

5((215-20y)/5)+20y=215

We move all terms to the left:

5((215-20y)/5)+20y-(215)=0

We add all the numbers together, and all the variables

5((-20y+215)/5)+20y-215=0

We add all the numbers together, and all the variables

20y+5((-20y+215)/5)-215=0

We multiply all the terms by the denominator


20y*5)+5((-20y+215)-215*5)=0

We add all the numbers together, and all the variables

20y*5)+5((-20y+215)=0

Wy multiply elements

100y^2=0

a = 100; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·100·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{200}=0$