5((3x-1)/7+2)=35

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Solution for 5((3x-1)/7+2)=35 equation: 



5((3x-1)/7+2)=35

We move all terms to the left:

5((3x-1)/7+2)-(35)=0

We multiply all the terms by the denominator


5((3x-1)-35*7+2)=0

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