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5((3x/7)-2)=3x
We move all terms to the left:
5((3x/7)-2)-(3x)=0
We add all the numbers together, and all the variables
5((+3x/7)-2)-3x=0
We add all the numbers together, and all the variables
-3x+5((+3x/7)-2)=0
We multiply all the terms by the denominator
-3x*7)-2)+5((+3x=0
We add all the numbers together, and all the variables
3x-3x*7)-2)+5((=0
Wy multiply elements
-21x^2+3x=0
a = -21; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-21)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-21}=\frac{-6}{-42} =1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-21}=\frac{0}{-42} =0 $
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