5((5-3y)/2)-2y=-16

Solution for 5((5-3y)/2)-2y=-16 equation:

5((5-3y)/2)-2y=-16

We move all terms to the left:

5((5-3y)/2)-2y-(-16)=0

We add all the numbers together, and all the variables

5((-3y+5)/2)-2y-(-16)=0

We add all the numbers together, and all the variables

-2y+5((-3y+5)/2)+16=0

We multiply all the terms by the denominator


-2y*2)+5((-3y+5)+16*2)=0

We add all the numbers together, and all the variables

-2y*2)+5((-3y+5)=0

Wy multiply elements

-4y^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-8}=0$