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5((x+4)/3=4x-1
We move all terms to the left:
5((x+4)/3-(4x-1)=0
Domain of the equation: 3-(4x-1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
-(4x-1)!=-3
x∈R
5((x+4)=0
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