5(+2x)=4(2+x)+3(x+1)+3

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Solution for 5(+2x)=4(2+x)+3(x+1)+3 equation: 



5(+2x)=4(2+x)+3(x+1)+3

We move all terms to the left:

5(+2x)-(4(2+x)+3(x+1)+3)=0

We add all the numbers together, and all the variables

5(+2x)-(4(x+2)+3(x+1)+3)=0

We multiply parentheses

10x-(4(x+2)+3(x+1)+3)=0



We calculate terms in parentheses: -(4(x+2)+3(x+1)+3), so:

4(x+2)+3(x+1)+3

We multiply parentheses

4x+3x+8+3+3

We add all the numbers together, and all the variables

7x+14

Back to the equation:

-(7x+14)



We get rid of parentheses

10x-7x-14=0

We add all the numbers together, and all the variables

3x-14=0

We move all terms containing x to the left, all other terms to the right

3x=14

x=14/3

x=4+2/3

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