5(-2b+4)=2(b+4)

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Solution for 5(-2b+4)=2(b+4) equation: 



5(-2b+4)=2(b+4)

We move all terms to the left:

5(-2b+4)-(2(b+4))=0

We multiply parentheses

-10b-(2(b+4))+20=0



We calculate terms in parentheses: -(2(b+4)), so:

2(b+4)

We multiply parentheses

2b+8

Back to the equation:

-(2b+8)



We get rid of parentheses

-10b-2b-8+20=0

We add all the numbers together, and all the variables

-12b+12=0

We move all terms containing b to the left, all other terms to the right

-12b=-12

b=-12/-12

b=1

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