5(-2y+2)-16=-10(1y-1)-16

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Solution for 5(-2y+2)-16=-10(1y-1)-16 equation: 



5(-2y+2)-16=-10(1y-1)-16

We move all terms to the left:

5(-2y+2)-16-(-10(1y-1)-16)=0

We add all the numbers together, and all the variables

5(-2y+2)-(-10(y-1)-16)-16=0

We multiply parentheses

-10y-(-10(y-1)-16)+10-16=0



We calculate terms in parentheses: -(-10(y-1)-16), so:

-10(y-1)-16

We multiply parentheses

-10y+10-16

We add all the numbers together, and all the variables

-10y-6

Back to the equation:

-(-10y-6)



We add all the numbers together, and all the variables

-10y-(-10y-6)-6=0

We get rid of parentheses

-10y+10y+6-6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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