5(-2y+4)=3(3y-2)=6

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Solution for 5(-2y+4)=3(3y-2)=6 equation: 



5(-2y+4)=3(3y-2)=6

We move all terms to the left:

5(-2y+4)-(3(3y-2))=0

We multiply parentheses

-10y-(3(3y-2))+20=0



We calculate terms in parentheses: -(3(3y-2)), so:

3(3y-2)

We multiply parentheses

9y-6

Back to the equation:

-(9y-6)



We get rid of parentheses

-10y-9y+6+20=0

We add all the numbers together, and all the variables

-19y+26=0

We move all terms containing y to the left, all other terms to the right

-19y=-26

y=-26/-19

y=1+7/19

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