5(-2z-2)=-2(6z-2)

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Solution for 5(-2z-2)=-2(6z-2) equation: 



5(-2z-2)=-2(6z-2)

We move all terms to the left:

5(-2z-2)-(-2(6z-2))=0

We multiply parentheses

-10z-(-2(6z-2))-10=0



We calculate terms in parentheses: -(-2(6z-2)), so:

-2(6z-2)

We multiply parentheses

-12z+4

Back to the equation:

-(-12z+4)



We get rid of parentheses

-10z+12z-4-10=0

We add all the numbers together, and all the variables

2z-14=0

We move all terms containing z to the left, all other terms to the right

2z=14

z=14/2

z=7

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