5(-3+2m)+4m=-7+4(4+2m)

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Solution for 5(-3+2m)+4m=-7+4(4+2m) equation: 



5(-3+2m)+4m=-7+4(4+2m)

We move all terms to the left:

5(-3+2m)+4m-(-7+4(4+2m))=0

We add all the numbers together, and all the variables

5(2m-3)+4m-(-7+4(2m+4))=0

We add all the numbers together, and all the variables

4m+5(2m-3)-(-7+4(2m+4))=0

We multiply parentheses

4m+10m-(-7+4(2m+4))-15=0



We calculate terms in parentheses: -(-7+4(2m+4)), so:

-7+4(2m+4)

determiningTheFunctionDomain
4(2m+4)-7

We multiply parentheses

8m+16-7

We add all the numbers together, and all the variables

8m+9

Back to the equation:

-(8m+9)



We add all the numbers together, and all the variables

14m-(8m+9)-15=0

We get rid of parentheses

14m-8m-9-15=0

We add all the numbers together, and all the variables

6m-24=0

We move all terms containing m to the left, all other terms to the right

6m=24

m=24/6

m=4

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