5(-3+2s)s=5

Solution for 5(-3+2s)s=5 equation:

5(-3+2s)s=5

We move all terms to the left:

5(-3+2s)s-(5)=0

We add all the numbers together, and all the variables

5(2s-3)s-5=0

We multiply parentheses

10s^2-15s-5=0

a = 10; b = -15; c = -5;
Δ = b2-4ac
Δ = -152-4·10·(-5)
Δ = 425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{425}=\sqrt{25*17}=\sqrt{25}*\sqrt{17}=5\sqrt{17}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5\sqrt{17}}{2*10}=\frac{15-5\sqrt{17}}{20}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5\sqrt{17}}{2*10}=\frac{15+5\sqrt{17}}{20}
$