5(-3+4c)=4(2c+4)+12+c

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Solution for 5(-3+4c)=4(2c+4)+12+c equation: 


Simplifying
5(-3 + 4c) = 4(2c + 4) + 12 + c
(-3 * 5 + 4c * 5) = 4(2c + 4) + 12 + c
(-15 + 20c) = 4(2c + 4) + 12 + c

Reorder the terms:
-15 + 20c = 4(4 + 2c) + 12 + c
-15 + 20c = (4 * 4 + 2c * 4) + 12 + c
-15 + 20c = (16 + 8c) + 12 + c

Reorder the terms:
-15 + 20c = 16 + 12 + 8c + c

Combine like terms: 16 + 12 = 28
-15 + 20c = 28 + 8c + c

Combine like terms: 8c + c = 9c
-15 + 20c = 28 + 9c

Solving
-15 + 20c = 28 + 9c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9c' to each side of the equation.
-15 + 20c + -9c = 28 + 9c + -9c

Combine like terms: 20c + -9c = 11c
-15 + 11c = 28 + 9c + -9c

Combine like terms: 9c + -9c = 0
-15 + 11c = 28 + 0
-15 + 11c = 28

Add '15' to each side of the equation.
-15 + 15 + 11c = 28 + 15

Combine like terms: -15 + 15 = 0
0 + 11c = 28 + 15
11c = 28 + 15

Combine like terms: 28 + 15 = 43
11c = 43

Divide each side by '11'.
c = 3.909090909

Simplifying
c = 3.909090909

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