5(-3+4x)=4(2x+4)-12x

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Solution for 5(-3+4x)=4(2x+4)-12x equation: 



5(-3+4x)=4(2x+4)-12x

We move all terms to the left:

5(-3+4x)-(4(2x+4)-12x)=0

We add all the numbers together, and all the variables

5(4x-3)-(4(2x+4)-12x)=0

We multiply parentheses

20x-(4(2x+4)-12x)-15=0



We calculate terms in parentheses: -(4(2x+4)-12x), so:

4(2x+4)-12x

We add all the numbers together, and all the variables

-12x+4(2x+4)

We multiply parentheses

-12x+8x+16

We add all the numbers together, and all the variables

-4x+16

Back to the equation:

-(-4x+16)



We get rid of parentheses

20x+4x-16-15=0

We add all the numbers together, and all the variables

24x-31=0

We move all terms containing x to the left, all other terms to the right

24x=31

x=31/24

x=1+7/24

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