5(-3+d)=3(3d-2)

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Solution for 5(-3+d)=3(3d-2) equation: 



5(-3+d)=3(3d-2)

We move all terms to the left:

5(-3+d)-(3(3d-2))=0

We add all the numbers together, and all the variables

5(d-3)-(3(3d-2))=0

We multiply parentheses

5d-(3(3d-2))-15=0



We calculate terms in parentheses: -(3(3d-2)), so:

3(3d-2)

We multiply parentheses

9d-6

Back to the equation:

-(9d-6)



We get rid of parentheses

5d-9d+6-15=0

We add all the numbers together, and all the variables

-4d-9=0

We move all terms containing d to the left, all other terms to the right

-4d=9

d=9/-4

d=-2+1/4

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