5(-3-7x)-7(x-8)=41

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Solution for 5(-3-7x)-7(x-8)=41 equation: 



5(-3-7x)-7(x-8)=41

We move all terms to the left:

5(-3-7x)-7(x-8)-(41)=0

We add all the numbers together, and all the variables

5(-7x-3)-7(x-8)-41=0

We multiply parentheses

-35x-7x-15+56-41=0

We add all the numbers together, and all the variables

-42x=0

x=0/-42

x=0

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