5(-3c+2)=6c-11

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Solution for 5(-3c+2)=6c-11 equation: 



5(-3c+2)=6c-11

We move all terms to the left:

5(-3c+2)-(6c-11)=0

We multiply parentheses

-15c-(6c-11)+10=0

We get rid of parentheses

-15c-6c+11+10=0

We add all the numbers together, and all the variables

-21c+21=0

We move all terms containing c to the left, all other terms to the right

-21c=-21

c=-21/-21

c=1

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