5(-3x-2)+(x-3)=-4(4x+5)+13

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Solution for 5(-3x-2)+(x-3)=-4(4x+5)+13 equation: 



5(-3x-2)+(x-3)=-4(4x+5)+13

We move all terms to the left:

5(-3x-2)+(x-3)-(-4(4x+5)+13)=0

We multiply parentheses

-15x+(x-3)-(-4(4x+5)+13)-10=0

We get rid of parentheses

-15x+x-(-4(4x+5)+13)-3-10=0



We calculate terms in parentheses: -(-4(4x+5)+13), so:

-4(4x+5)+13

We multiply parentheses

-16x-20+13

We add all the numbers together, and all the variables

-16x-7

Back to the equation:

-(-16x-7)



We add all the numbers together, and all the variables

-14x-(-16x-7)-13=0

We get rid of parentheses

-14x+16x+7-13=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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