5(-3x-2)-(x-3)=-4(4x+5)+13=

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Solution for 5(-3x-2)-(x-3)=-4(4x+5)+13= equation: 



5(-3x-2)-(x-3)=-4(4x+5)+13=

We move all terms to the left:

5(-3x-2)-(x-3)-(-4(4x+5)+13)=0

We multiply parentheses

-15x-(x-3)-(-4(4x+5)+13)-10=0

We get rid of parentheses

-15x-x-(-4(4x+5)+13)+3-10=0



We calculate terms in parentheses: -(-4(4x+5)+13), so:

-4(4x+5)+13

We multiply parentheses

-16x-20+13

We add all the numbers together, and all the variables

-16x-7

Back to the equation:

-(-16x-7)



We add all the numbers together, and all the variables

-16x-(-16x-7)-7=0

We get rid of parentheses

-16x+16x+7-7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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