5(-4r+1)=7r-5(6r-7)

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Solution for 5(-4r+1)=7r-5(6r-7) equation: 



5(-4r+1)=7r-5(6r-7)

We move all terms to the left:

5(-4r+1)-(7r-5(6r-7))=0

We multiply parentheses

-20r-(7r-5(6r-7))+5=0



We calculate terms in parentheses: -(7r-5(6r-7)), so:

7r-5(6r-7)

We multiply parentheses

7r-30r+35

We add all the numbers together, and all the variables

-23r+35

Back to the equation:

-(-23r+35)



We get rid of parentheses

-20r+23r-35+5=0

We add all the numbers together, and all the variables

3r-30=0

We move all terms containing r to the left, all other terms to the right

3r=30

r=30/3

r=10

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