5(-m+1)=2(m-1)+28

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Solution for 5(-m+1)=2(m-1)+28 equation: 



5(-m+1)=2(m-1)+28

We move all terms to the left:

5(-m+1)-(2(m-1)+28)=0

We add all the numbers together, and all the variables

5(-1m+1)-(2(m-1)+28)=0

We multiply parentheses

-5m-(2(m-1)+28)+5=0



We calculate terms in parentheses: -(2(m-1)+28), so:

2(m-1)+28

We multiply parentheses

2m-2+28

We add all the numbers together, and all the variables

2m+26

Back to the equation:

-(2m+26)



We get rid of parentheses

-5m-2m-26+5=0

We add all the numbers together, and all the variables

-7m-21=0

We move all terms containing m to the left, all other terms to the right

-7m=21

m=21/-7

m=-3

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