5(-m+10)10m=+2-8m

Solution for 5(-m+10)10m=+2-8m equation:

5(-m+10)10m=+2-8m

We move all terms to the left:

5(-m+10)10m-(+2-8m)=0

We add all the numbers together, and all the variables

5(-1m+10)10m-(-8m+2)=0

We multiply parentheses

-50m^2+500m-(-8m+2)=0

We get rid of parentheses

-50m^2+500m+8m-2=0

We add all the numbers together, and all the variables

-50m^2+508m-2=0

a = -50; b = 508; c = -2;
Δ = b2-4ac
Δ = 5082-4·(-50)·(-2)
Δ = 257664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{257664}=\sqrt{64*4026}=\sqrt{64}*\sqrt{4026}=8\sqrt{4026}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(508)-8\sqrt{4026}}{2*-50}=\frac{-508-8\sqrt{4026}}{-100}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(508)+8\sqrt{4026}}{2*-50}=\frac{-508+8\sqrt{4026}}{-100}
$