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5(0.25p-1)=5/4p-2.4
We move all terms to the left:
5(0.25p-1)-(5/4p-2.4)=0
Domain of the equation: 4p-2.4)!=0We multiply parentheses
p∈R
0p-(5/4p-2.4)-5=0
We get rid of parentheses
0p-5/4p+2.4-5=0
We multiply all the terms by the denominator
0p*4p+(2.4)*4p-5*4p-5=0
We multiply parentheses
0p*4p+9.6p-5*4p-5=0
Wy multiply elements
0p^2+9.6p-20p-5=0
We add all the numbers together, and all the variables
p^2-10.4p-5=0
a = 1; b = -10.4; c = -5;
Δ = b2-4ac
Δ = -10.42-4·1·(-5)
Δ = 128.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.4)-\sqrt{128.16}}{2*1}=\frac{10.4-\sqrt{128.16}}{2} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.4)+\sqrt{128.16}}{2*1}=\frac{10.4+\sqrt{128.16}}{2} $
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