5(1+)=6(2+c)

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Solution for 5(1+)=6(2+c) equation: 



5(1+)=6(2+c)

We move all terms to the left:

5(1+)-(6(2+c))=0

We add all the numbers together, and all the variables

-(6(c+2))+50=0



We calculate terms in parentheses: -(6(c+2)), so:

6(c+2)

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)



We get rid of parentheses

-6c-12+50=0

We add all the numbers together, and all the variables

-6c+38=0

We move all terms containing c to the left, all other terms to the right

-6c=-38

c=-38/-6

c=6+1/3

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