5(1+2)=1/2(8+20m)

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Solution for 5(1+2)=1/2(8+20m) equation: 



5(1+2)=1/2(8+20m)

We move all terms to the left:

5(1+2)-(1/2(8+20m))=0



Domain of the equation: 2(8+20m))!=0

m∈R



We add all the numbers together, and all the variables

-(1/2(20m+8))+53=0

We multiply all the terms by the denominator


-(1+53*2(20m+8))=0



We calculate terms in parentheses: -(1+53*2(20m+8)), so:

1+53*2(20m+8)

determiningTheFunctionDomain
53*2(20m+8)+1

Wy multiply elements

106m(2+1

Back to the equation:

-(106m(2+1)



We add all the numbers together, and all the variables

-(106m3=0

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