5(1+2)=8(i-1)

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Solution for 5(1+2)=8(i-1) equation: 



5(1+2)=8(i-1)

We move all terms to the left:

5(1+2)-(8(i-1))=0

We add all the numbers together, and all the variables

-(8(i-1))+53=0



We calculate terms in parentheses: -(8(i-1)), so:

8(i-1)

We multiply parentheses

8i-8

Back to the equation:

-(8i-8)



We get rid of parentheses

-8i+8+53=0

We add all the numbers together, and all the variables

-8i+61=0

We move all terms containing i to the left, all other terms to the right

-8i=-61

i=-61/-8

i=7+5/8

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