5(1+2m)=1/2(7+20m)

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Solution for 5(1+2m)=1/2(7+20m) equation: 



5(1+2m)=1/2(7+20m)

We move all terms to the left:

5(1+2m)-(1/2(7+20m))=0



Domain of the equation: 2(7+20m))!=0

m∈R



We add all the numbers together, and all the variables

5(2m+1)-(1/2(20m+7))=0

We multiply parentheses

10m-(1/2(20m+7))+5=0

We multiply all the terms by the denominator


10m*2(20m+7))-(1+5*2(20m+7))=0

Wy multiply elements

20m^2(2+10m(2=0

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