5(1+2m)=1/2(8+20m)

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Solution for 5(1+2m)=1/2(8+20m) equation: 


m in (-oo:+oo)

5*(2*m+1) = (1/2)*(20*m+8) // - (1/2)*(20*m+8)

5*(2*m+1)-((1/2)*(20*m+8)) = 0

5*(2*m+1)+(-1/2)*(20*m+8) = 0

5*(2*m+1)-1/2*(20*m+8) = 0

5*(2*m+1)-1/2*(20*m+8) = 0

1 = 0

1 = 0

m belongs to the empty set

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