5(1+2m)=1/2(8+29m)

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Solution for 5(1+2m)=1/2(8+29m) equation:



5(1+2m)=1/2(8+29m)
We move all terms to the left:
5(1+2m)-(1/2(8+29m))=0
Domain of the equation: 2(8+29m))!=0
m∈R
We add all the numbers together, and all the variables
5(2m+1)-(1/2(29m+8))=0
We multiply parentheses
10m-(1/2(29m+8))+5=0
We multiply all the terms by the denominator
10m*2(29m+8))-(1+5*2(29m+8))=0
Wy multiply elements
20m^2(2+10m(2=0

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